Distinct but related quantities that are easy to mix up
Surface and soil temperatures can be a risk for plants, hence there are several practices aimed to reduce heat or frost stress.
Soil temperatures are controlled by available energy
Varies with latitude and proximity to the coast in BC
Also influenced by topography, soil type, and moisture
Heat: is thermal energy.
Temperature a (relative) measure of thermal energy.
Heat capacity (\(C\)) is the quantity of heat required to raise the temperature of a unit volume (e.g., 1 m-3) of a material 1 K.
Material | Heat capacity MJ m-3 K |
---|---|
Air | 0.0012 |
Water (liquid) | 4.1800 |
Ice | 1.9000 |
Soil mineral | 2.1000 |
Soil organic matter | 2.5000 |
Wood organic matter | 2.0000 |
You run an experiment using a camping stove with a 1 liter pan to heat up four different substances. You run the stover for the same amount of time (1 minute) and use the same volume of each substance (exactly 1 liter). All substances start at the same temperature (15 \(^{\circ} C\)); which substance will have the highest temperature at the end of the 1 minute period?
Specific heat \(c\) is the quantity of heat required to raise the temperature of a unit mass (e.g., 1 Kg) of a material 1 K.
Material | Specific heat kJ kg-1 K-1 |
---|---|
Air | 1.01 |
Water (liquid) | 4.18 |
Ice | 2.10 |
Soil mineral | 0.80 |
Soil organic matter | 1.90 |
Wood organic matter | 1.30 |
Density (\(\rho\)) of the material:
\[ C=\rho c \qquad(1)\]
Example of water:
\(C =\) 1 Mg m-3 \(x\) 4.18 J kg-1 K-1 =
4.18 J6 m-3 K-1 = 4.18 MJ m-3 K-1
Material | Density Mg m-3 |
---|---|
Air | 0.0012 |
Water (liquid) | 1.0000 |
Ice | 0.9000 |
Soil mineral | 2.6500 |
Soil organic matter | 1.3000 |
Wood organic matter | 1.5000 |
The heat capacity of a mixture of substances can be calculated from the heat capacity and volume fraction of each component. For soil:
\[ C_{soil}=C_{m}\theta_{m}+C_{o}\theta_{o}+C_{w}\theta_{w}+C_{a}\theta_{a} \qquad(2)\]
Material | Heat capacity MJ m-3 K |
---|---|
Air | 0.0012 |
Water (liquid) | 4.1800 |
Ice | 1.9000 |
Soil mineral | 2.1000 |
Soil organic matter | 2.5000 |
Wood organic matter | 2.0000 |
We have a soil that is 45% minerals and 0% organic matter by volume. The rest is pore space (for air or water).
Dry Mineral Soil
\(C =\) 0.94566 MJ m-3 K-1
We have a soil that is 0% minerals and 45% organic matter by volume and 25% water by volume. What would it’s heat capacity be in MJ m-3 K-1?
Wet (not saturated) Organic Soil
\(C =\) 2.17036 MJ m-3 K-1
Organic soils usually have high porosity, so they can hold more water so more heat is required to warm them compared to mineral soils.
Mixture | % H2O content | Density(Mg m-3) | Heat capacity C(MJ m-3 K-1) |
---|---|---|---|
Mineral soil (dry / saturated) | 0 / 0.55 | 1.20 / 1.75 | 0.90 / 3.2 |
Wood (dry / saturated) | 0 / 0.60 | 0.60 / 1.20 | 0.80 / 3.3 |
Peat soil (dry / saturated) | 0 / 0.85 | 0.20 / 1.05 | 0.40 / 3.9 |
Animal / plant tissue | ~0.9 | 1.1 | 3.7 |
Describes the transfer of heat through a volume of soil.
\[ \frac{H_g}{z} = C \frac{\Delta T_s}{t} \qquad(3)\]
Positive indicates a surplus of energy at the surface being transferred downwards through the soil via conduction. Negative indicates a surplus at depth being transferred upwards through the soil via conduction.
\(H_g\) will be correlated with \(R_n\), though its not a direct relationship, and the strength of the relationship will vary by site conditions.
The higher C, the smaller the rate of temperature change.
Given same amount of energy input by radiation (e.g. same day), which soil will warm up more rapidly? The photos show the same location:
We have a mineral soil with \(\approx\) 30% water content by volume, giving it C = 2 MJ m-3 K-1. With a soil heat flux (H) of 100 W m-2 going into the soil surface layer of depth z = 0.1 m. Rearranging Equation 3 we can solve for \(\Delta T\):
\(\frac{\Delta T}{t} = \frac{1}{C}\frac{H_g}{z}\)
\(\frac{\Delta T}{t} = \frac{1}{2 MJ m^{-3} K^{-1}}\frac{100 J m^{-2} s^{-1}}{0.1 m}\)
0.0005 K s-1 = 1.8 K H-1
You run an experiment using camping stove with a 1 liter pan to heat up four different substances. You run the stover for the same amount of time (1 minute) and use the same volume of each substance (exactly 1 liter). All substances start at the same temperature (15 \(^{\circ} C\)); which substance will have the lowest temperature at the end of the 1 minute period?